3x^2+26x+168=2x^2

Solution for 3x^2+26x+168=2x^2 equation:

3x^2+26x+168=2x^2

We move all terms to the left:

3x^2+26x+168-(2x^2)=0

determiningTheFunctionDomain
3x^2-2x^2+26x+168=0

We add all the numbers together, and all the variables

x^2+26x+168=0

a = 1; b = 26; c = +168;
Δ = b2-4ac
Δ = 262-4·1·168
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2}{2*1}=\frac{-28}{2}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2}{2*1}=\frac{-24}{2}
=-12
$